How * in Rust can get the actual value of &T?
⚓ Rust 📅 2025-10-16 👤 surdeus 👁️ 8Hi guys, I am new to Rust. I have some questions about the concept of "Dereferencing" using *
I have read some posts and answers on this site, but things still seem unclear to a newbie like me. My questions are as follows:
How * in Rust get the actual value of a reference? While i see the definition of * (deref method from std::ops::Deref) will return a reference to a type T (&T), not the actual value. But when i use *, the result i get is the actual value, not the reference to that actual value.
If my question is not clear, or I have missed anything in this post, I hope everyone will give me feedback so I can change it. Thanks everyone.
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